1+3ab-28a^2b^2=

Solution for 1+3ab-28a^2b^2= equation:

Simplifying
1 + 3ab + -28a2b2 = 0

Solving
1 + 3ab + -28a2b2 = 0

Solving for variable 'a'.

Factor a trinomial.
(1 + -4ab)(1 + 7ab) = 0

Subproblem 1
Set the factor '(1 + -4ab)' equal to zero and attempt to solve:

Simplifying
1 + -4ab = 0

Solving
1 + -4ab = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4ab = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4ab = 0 + -1
-4ab = 0 + -1

Combine like terms: 0 + -1 = -1
-4ab = -1

Divide each side by '-4b'.
a = 0.25b-1

Simplifying
a = 0.25b-1
Subproblem 2
Set the factor '(1 + 7ab)' equal to zero and attempt to solve:

Simplifying
1 + 7ab = 0

Solving
1 + 7ab = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7ab = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 7ab = 0 + -1
7ab = 0 + -1

Combine like terms: 0 + -1 = -1
7ab = -1

Divide each side by '7b'.
a = -0.1428571429b-1

Simplifying
a = -0.1428571429b-1
Solution
a = {0.25b-1, -0.1428571429b-1}